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Posted by Sam E on October 25, 2009, 12:05 pm
[snip]
>Oh, you mean that if both legs are fully loaded, there's no current being
>drawn at all?
>Sorry, but you don't understand. The current in the neutral is in fact zero,
>if both legs are loaded exactly equally -- and if all the loads supplied are
>120V loads, then it is in fact drawing 400A @ 120V.
That current is 200A. That 400A is obviously not in the neutral. WHERE
is it?
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Posted by Doug Miller on October 25, 2009, 2:46 pm
>[snip]
>>Oh, you mean that if both legs are fully loaded, there's no current being
>>drawn at all?
>>Sorry, but you don't understand. The current in the neutral is in fact zero,
>>if both legs are loaded exactly equally -- and if all the loads supplied are
>>120V loads, then it is in fact drawing 400A @ 120V.
>That current is 200A. That 400A is obviously not in the neutral. WHERE
>is it?
There's no current in the neutral if the loads are balanced.
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Posted by Sam E on October 25, 2009, 9:15 pm
On Sun, 25 Oct 2009 18:46:17 GMT, spambait@milmac.com (Doug Miller)
wrote:
>>[snip]
>>>Oh, you mean that if both legs are fully loaded, there's no current being
>>>drawn at all?
>>>Sorry, but you don't understand. The current in the neutral is in fact zero,
>>>if both legs are loaded exactly equally -- and if all the loads supplied are
>>>120V loads, then it is in fact drawing 400A @ 120V.
>>That current is 200A. That 400A is obviously not in the neutral. WHERE
>>is it?
>There's no current in the neutral if the loads are balanced.
No current. I was replying to the person who claimed 400A.
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Posted by JIMMIE on October 26, 2009, 12:56 am
> On Sun, 25 Oct 2009 18:46:17 GMT, spamb...@milmac.com (Doug Miller)
> wrote:
@all.invalid> wrote:
> >>[snip]
> >>>Oh, you mean that if both legs are fully loaded, there's no current be=
ing
> >>>drawn at all?
> >>>Sorry, but you don't understand. The current in the neutral is in fact=
zero,
> >>>if both legs are loaded exactly equally -- and if all the loads suppli=
ed are
> >>>120V loads, then it is in fact drawing 400A @ 120V.
> >>That current is 200A. That 400A is obviously not in the neutral. WHERE
> >>is it?
> >There's no current in the neutral if the loads are balanced.
> No current. I was replying to the person who claimed 400A.
Assume you are using one leg at 200 amps, that is all the breaker
will handle that is 120 volts X 200 amps or 24,000 watts. If you
again max out the breaker with 200 amps flowing on both sides that is
240 volts x 200 amps or 48000 watts. Thats the same as 120 X 400 amps.
I think the OP wanted to know if he could get a total of 400 amps at
120VAC. Lets rephrase that to could he power 400 1 amp 120 VAC loads
from this box under residential conditions. The answer is yes but that
sounds a lot like a commercial installation to me where the answer
would be NO. I think this is a case of getting the right answers to
the wrong question.
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Posted by on October 26, 2009, 10:37 am
On Sun, 25 Oct 2009 18:46:17 GMT, in alt.home.repair, spambait@milmac.com
(Doug Miller) wrote:
>>[snip]
>>>Oh, you mean that if both legs are fully loaded, there's no current being
>>>drawn at all?
>>>Sorry, but you don't understand. The current in the neutral is in fact zero,
>>>if both legs are loaded exactly equally -- and if all the loads supplied are
>>>120V loads, then it is in fact drawing 400A @ 120V.
>>That current is 200A. That 400A is obviously not in the neutral. WHERE
>>is it?
>There's no current in the neutral if the loads are balanced.
How can people get this so wrong? It's basic electricity, you all should
have learned this in high school.
In a 200A 240V split phase service, any SINGLE 120v load can draw up to
200A, no more. Because it is split phase, you can have two such loads. Now
the math. 200A@120V + 200A@120V = 200A@240V, NOT 400A@120V. Because two
200A 120V loads on a single split phase panel are in fact operating in
series (whether you deliberately wired them that way or not), presenting a
de facto 200A 240V load on the panel. And, yes, in that case the neutral
conductor current is zero.
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>drawn at all?
>Sorry, but you don't understand. The current in the neutral is in fact zero,
>if both legs are loaded exactly equally -- and if all the loads supplied are
>120V loads, then it is in fact drawing 400A @ 120V.