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Math question SteveB 10-07-2009
---> Re: Math question norminn@earthli...10-07-2009
---> Re: Math question John H. Hollida...10-07-2009
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Posted by Metspitzer on October 7, 2009, 3:25 pm


wrote:

>How do I figure the area of a pool from the perimeter? It is a kidney
>shaped (exaggerated) pool.
>Steve
0.45 x (A+B) x length x average depth x 7.5 = volume (in gallons) of
kidney or irregular-shaped pool
http://www.1paramount.com/poolcare/formulas.php
Google is your friend

Posted by blueman on October 7, 2009, 5:34 pm



> wrote:
>>How do I figure the area of a pool from the perimeter? It is a kidney
>>shaped (exaggerated) pool.
>>Steve
> 0.45 x (A+B) x length x average depth x 7.5 = volume (in gallons) of
> kidney or irregular-shaped pool
> http://www.1paramount.com/poolcare/formulas.php
> Google is your friend

The OP asked for AREA not volume in gallons.
Also your formula at best is some vague type of approximation since
there is no standard kidney-shape and certainly irregular-shaped is
even less well-defined. Although since the site doesn't define what A
and B are, the formula will by definition be true for some values of A
and B ;)

Posted by David Combs on November 2, 2009, 12:52 am


>> wrote:
>>>How do I figure the area of a pool from the perimeter? It is a kidney
>>>shaped (exaggerated) pool.
>>>Steve
>> 0.45 x (A+B) x length x average depth x 7.5 = volume (in gallons) of
>> kidney or irregular-shaped pool
>> http://www.1paramount.com/poolcare/formulas.php
>> Google is your friend
>The OP asked for AREA not volume in gallons.
>Also your formula at best is some vague type of approximation since
>there is no standard kidney-shape and certainly irregular-shaped is
>even less well-defined. Although since the site doesn't define what A
>and B are, the formula will by definition be true for some values of A
>and B ;)


Learned this once (and yes, it has a name that I don't remember):

For symmetrical even if then leaned over -- something like that,
sphere, cone, etc:

Volume = area of top + 4 * area of middle (cross section, I guess) +
area of bottom, all divided by 6.


David




Posted by blueman on November 5, 2009, 1:55 am


dkcombs@panix.com (David Combs) writes:
>>> wrote:
>>>>How do I figure the area of a pool from the perimeter? It is a kidney
>>>>shaped (exaggerated) pool.
>>>>Steve
>>> 0.45 x (A+B) x length x average depth x 7.5 = volume (in gallons) of
>>> kidney or irregular-shaped pool
>>> http://www.1paramount.com/poolcare/formulas.php
>>> Google is your friend
>>The OP asked for AREA not volume in gallons.
>>Also your formula at best is some vague type of approximation since
>>there is no standard kidney-shape and certainly irregular-shaped is
>>even less well-defined. Although since the site doesn't define what A
>>and B are, the formula will by definition be true for some values of A
>>and B ;)
> Learned this once (and yes, it has a name that I don't remember):
> For symmetrical even if then leaned over -- something like that,
> sphere, cone, etc:
> Volume = area of top + 4 * area of middle (cross section, I guess) +
> area of bottom, all divided by 6.

Your formula is certainly in general FALSE since volume is
3-dimensional and grows to first order as the cube of some notion of
"radius" while your formula is just a weighted sum of 3
cross-sections.

Volume is volume.
Area is area.
Irregular shapes don't in general have nice formulas and require
numerical approximation/integration.

Posted by norminn@earthlink.net on October 7, 2009, 3:32 pm


SteveB wrote:
> How do I figure the area of a pool from the perimeter? It is a kidney
> shaped (exaggerated) pool.
>
> Steve
>
>

How critical is the measurement? I would sketch out the length and
width, cut off triangles for the belly of the kidney and outside the
curves....area of the rectangle less the areas (roughly triangular)
outside of the curves should give a fairly close measurement.

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