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Using 1" thick cedar decking okay?

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Using 1" thick cedar decking okay? Ken Moiarty 06-13-2005
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Posted by J on June 14, 2005, 4:52 pm
>
> > Actually it has much less than half the bending strength. Resistance to
> > bending is proportional to the cube of the depth.
>
> Admittedly it was 30 years ago and things change, but when I took
mechanical
> engineering it was proportional to the square. You integrated the
material
> multiplied by it's distance from the center; that means squared, no?


Perhaps you didn't do that well in mechanical engineering... :-)

Moment of inertia (I) for a rectangular beam with width b and height h has
been

I = bh^3/12

for as long as I can recall.

And for deflection (d) of a simply supported beam we use the formula

d = PL^3/48EI

Other formulas for bending (canteliever, multiple supports ...) vary, but
all the ones I can recall off the top of my head include I in the
denominator.
Therefore I am certain that I did mean cubed and did not mean squared.

-j



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Posted by Peter James on June 14, 2005, 10:45 pm
J wrote:
>
>>>Actually it has much less than half the bending strength. Resistance to
>>>bending is proportional to the cube of the depth.
>>
>>Admittedly it was 30 years ago and things change, but when I took
>>mechanical engineering it was proportional to the square.
>>You integrated the material multiplied by it's distance from the
>>center; that means squared, no?
>
> Perhaps you didn't do that well in mechanical engineering... :-)
>
> Moment of inertia (I) for a rectangular beam with width b and height
> h has been I = bh^3/12 for as long as I can recall.
>
> And for deflection (d) of a simply supported beam we use the formula
> d = PL^3/48EI
>
> Other formulas for bending (canteliever, multiple supports ...) vary, but
> all the ones I can recall off the top of my head include I in the
> denominator.
> Therefore I am certain that I did mean cubed and did not mean squared.
>
> -j
>
>


Well - you're confusing bending strength and deflection. In your first
post you said:

Quote:        Actually it has much less than half the bending strength.
Resistance to bending is proportional to the cube of the depth.

This is incorrect - bending strength is governed by stress, which is
derived from bh^2/6 - the square of depth, as "toller" noted.

But in your second post you introduced deflection:

Quote:        Moment of inertia (I) for a rectangular beam with width b and
height h has been I = bh^3/12 for as long as I can recall.

This is correct - for deflection.

--
Peter James

Posted by J on June 15, 2005, 3:29 pm
> J wrote:
> >
> >>>Actually it has much less than half the bending strength. Resistance to
> >>>bending is proportional to the cube of the depth.
> >>
> >>Admittedly it was 30 years ago and things change, but when I took
> >>mechanical engineering it was proportional to the square.
> >>You integrated the material multiplied by it's distance from the
> >>center; that means squared, no?
> >
> > Perhaps you didn't do that well in mechanical engineering... :-)
> >
> > Moment of inertia (I) for a rectangular beam with width b and height
> > h has been I = bh^3/12 for as long as I can recall.
> >
> > And for deflection (d) of a simply supported beam we use the formula
> > d = PL^3/48EI
> >
> > Other formulas for bending (canteliever, multiple supports ...) vary,
but
> > all the ones I can recall off the top of my head include I in the
> > denominator.
> > Therefore I am certain that I did mean cubed and did not mean squared.
> >
> > -j
> >
> >
>
>
> Well - you're confusing bending strength and deflection. In your first
> post you said:
>
> Quote: Actually it has much less than half the bending strength.
> Resistance to bending is proportional to the cube of the depth.
>
> This is incorrect - bending strength is governed by stress, which is
> derived from bh^2/6 - the square of depth, as "toller" noted.
>
> But in your second post you introduced deflection:
>
> Quote: Moment of inertia (I) for a rectangular beam with width b and
> height h has been I = bh^3/12 for as long as I can recall.
>
> This is correct - for deflection.

Yep, I got a step ahead of myself and forgot I even mentioned bending
strength.

-j



Posted by toller on June 16, 2005, 12:04 am

>J wrote:
>>
>>>>Actually it has much less than half the bending strength. Resistance to
>>>>bending is proportional to the cube of the depth.
>>>
>>>Admittedly it was 30 years ago and things change, but when I took
>>>mechanical engineering it was proportional to the square.
> >>You integrated the material multiplied by it's distance from the
> >>center; that means squared, no?
>>
>> Perhaps you didn't do that well in mechanical engineering... :-)
>>
>> Moment of inertia (I) for a rectangular beam with width b and height
>> h has been I = bh^3/12 for as long as I can recall.
>>
>> And for deflection (d) of a simply supported beam we use the formula
>> d = PL^3/48EI
>>
>> Other formulas for bending (canteliever, multiple supports ...) vary, but
>> all the ones I can recall off the top of my head include I in the
>> denominator.
>> Therefore I am certain that I did mean cubed and did not mean squared.
>>
>> -j
>>
>
>
> Well - you're confusing bending strength and deflection. In your first
> post you said:
>
> Quote: Actually it has much less than half the bending strength.
> Resistance to bending is proportional to the cube of the depth.
>
> This is incorrect - bending strength is governed by stress, which is
> derived from bh^2/6 - the square of depth, as "toller" noted.
>
Thank you Peter; good to know I am not senile yet.



Posted by Tony Hwang on June 13, 2005, 6:22 pm
Ken Moiarty wrote:

> I'm trying to decide whether to go with inexpensive pressure-treated
> evergreen wood decking or low cost 1" thick (approx.), radius edge, cedar
> (which is must less expensive than standard patio grade cedar decking). I
> kind of prefer the cedar option, but I'm unsure about whether it's wise to
> go with cedar that is only half the thickness (hence, half the strength) as
> standard patio grade cedar. My concern is not about safety per se so much
> as it is about structural rigidity, solidness, etc. I don't want it to feel
> like I'm 'bouncing on planks' when walking on the deck. Any suggestions,
> advice, experiences? Thanks...
>
> Ken
>
>
Hi,
My deck out at cabin has that cedar decking. Smooth round edge like
flooring material. Used deck screws for fastening. Over 5 years, yet
no problem. I think your joist strength and spacing is more important.
Tony

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