Wind force

	Wind force

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Subject

Author

Date

Wind force

dadiOH

06-14-2006

J. Clarke

nicksanspam

dadiOH

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Posted by dadiOH on June 14, 2006, 9:57 am

Can someone tell me how to compute the force for a given wind velocity
against a solid object per square foot in pounds? For example, 40 mph wind,
object 10 square ft...weight per square foot = ? pounds to keep object from
being moved by wind.

--

dadiOH

Posted by J. Clarke on June 14, 2006, 10:32 am

dadiOH wrote:

> Can someone tell me how to compute the force for a given wind velocity

> against a solid object per square foot in pounds? For example, 40 mph

> wind, object 10 square ft...weight per square foot = ? pounds to keep

> object from being moved by wind.

You might find <http://timber.ce.wsu.edu/Supplements/WindDesign/PAGE1.asp>
to be of interest.

--
--John
to email, dial "usenet" and validate
(was jclarke at eye bee em dot net)

Posted by on June 14, 2006, 11:09 am

>Can someone tell me how to compute the force for a given wind velocity

>against a solid object per square foot in pounds?

P = 0.00256V^2 psf, eg 4 psf for V = 40 mph.

>For example, 40 mph wind, object 10 square ft...weight per square foot = ?

>pounds to keep object from being moved by wind.

With 10 ft^2 facing the wind, the sliding force would be 40 pounds.
So if the coefficient of friction with the surface below were 1,
it would need to weigh at least 40 pounds to avoid sliding.

If it were (say) 6' tall and symmetrical, the overturning moment would be
40x6/2 = 120 foot-pounds. If it were 4' long in the wind direction and
the 6' projection were in the middle, the resisting moment arm would be
4/2 = 2'. If it weighed P pounds, 120 = 2P would make P = 60 pounds min.

Nick

Posted by dadiOH on June 15, 2006, 6:47 am

dadiOH wrote:

Thanks, both...I now have the info I needed.

--

dadiOH
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