Wind force

Posted by dadiOH on June 14, 2006, 9:57 am

Can someone tell me how to compute the force for a given wind velocity
against a solid object per square foot in pounds? For example, 40 mph wind,
object 10 square ft...weight per square foot = ? pounds to keep object from
being moved by wind.
--
dadiOH

Posted by J. Clarke on June 14, 2006, 10:32 am

dadiOH wrote:
show/hide quoted text
to be of interest.
--
--John
to email, dial "usenet" and validate
(was jclarke at eye bee em dot net)

Posted by nicksanspam on June 14, 2006, 11:09 am

show/hide quoted text
P = 0.00256V^2 psf, eg 4 psf for V = 40 mph.
show/hide quoted text
With 10 ft^2 facing the wind, the sliding force would be 40 pounds.
So if the coefficient of friction with the surface below were 1,
it would need to weigh at least 40 pounds to avoid sliding.
If it were (say) 6' tall and symmetrical, the overturning moment would be
40x6/2 = 120 foot-pounds. If it were 4' long in the wind direction and
the 6' projection were in the middle, the resisting moment arm would be
4/2 = 2'. If it weighed P pounds, 120 = 2P would make P = 60 pounds min.
Nick

Posted by dadiOH on June 15, 2006, 6:47 am

dadiOH wrote:
Thanks, both...I now have the info I needed.
--
dadiOH
____________________________
dadiOH's dandies v3.06...
...a help file of info about MP3s, recording from
LP/cassette and tips & tricks on this and that.
Get it at http://mysite.verizon.net/xico

Similar Threads	Posted
How much force to tip over a tree	October 23, 2006, 12:19 am
Force 10 shower	July 31, 2007, 11:02 am
Teflon or brute force	July 5, 2007, 6:43 pm
Genie garage door opener force adjustment?	December 7, 2009, 8:56 am
Wind powered car	March 19, 2006, 5:05 am
Wind up flashlight	December 26, 2007, 5:05 pm
Wind fence question	January 6, 2006, 11:56 am
Shingles / wind question	June 14, 2006, 4:50 pm
wind in the fireplace insert	February 2, 2007, 7:43 pm
Flooolight keeps turning on because of wind.	January 9, 2010, 1:22 am